Area enclosed between log & coordinate axes

Ask

The area enclosed between the curve $ y = log _{e} ( x + e ) $ and the coordinate axes is

( a ) 1 ( b ) 2 ( c ) 3 ( d ) 4

Answer is ( )

Integral of Log 

∫ {[(log x -1)/1+(log x)^2]^2}dx

is equal to

( a ) log x/ [1 +( log x)^2]+ c

( b ) x/(x^2+1) + c

( c ) xe^x/(1+ x^2)+ c

( d ) x/[(log x)^2+1]+c

Concept

Type Reasoning here