Steady State Error 1.1

Ask

A system has position error constant $K_p = 3$. The steady error for input of 8tu(t) is

(a) 2.67

(b) 2

(c) $\infty$

(d) 0

Answer is (c  )

Concept

Positional Error Constant $K_p = 3$ , Input Signal = $r(t) = 8tu(t)$

$R(s) = \frac{8}{s^2}$ , Input signal is Ramp type, velocity error constant $K_v = 0$

Steady State Error $e_ss = 1/K_v = \infty$