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A second order system exibhits 100% overshoot.It's damping coefficient is
(a)0
(b)1
(c)< 1
(d)> 1
Answer is ( a )
Concept
Explanation:For a second order system , Peak OverShoot is M_p = 100 %M_p = e^{\frac{-\zeta}{\sqrt{1-\zeta^2}}}e^{\frac{-\zeta}{\sqrt{1-\zeta^2}}} = 100% = 1Taking Logarithm on both sides,\frac{-\zeta}{\sqrt{1-\zeta^2}} = ln(1) = 0This implies, \zeta = 0This indicates no damping
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