Transistor Cutoff

Ask

For a transistor in cutoff state, $V_{ce}$ will be approximately equal to
(a) $V_{cc}$
(b) $V_b$
(c) 0.2V
(d) 0.7V

Answer is (a)

Concept

Applying KVL to the circuit, Vcc = IcRc-Vce When the transistor is open, there is no current flow and thus Ic will be zero. Thus Vcc = Vce