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DE.3) The output frequency of a frequency division circuit that contains 12 flip-flops with an input clock frequency of 20.48 MHz is
(a) 10.24 kHz
(b) 5 kHz
(c) 30.24 kHz
(d) 15 kHz
Answer is (b)
Concept
Output frequency = $\frac{input frequency}{(2^{n})}$ where n is the number of flip flops.Thus fout$f_{out} = \frac{20.48MHz}{2^{12}}$= 20.48MHz/4096= 5 KHz
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