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Carrier Concentration

Ask
Silicon is doped with boron to a concentration of 4x1017  atoms per cubic centimeters (atoms/cm3). Assume the intrinsic carrier concentration of silicon to be 1.5x1010 per cubic centimeters (atoms/cm3) and the value of kT/q to be 25mV at 300K. Compared to undoped silicon , the Fermi level of doped silicon:
(a) goes sown by 0.13 eV
(b) goes up by 0.13eV
(c) goes down by 0.427 eV
(d) goes up by 0.427 eV

Answer is (c)
Concept

{N_A} = 4\times 10^{17}
{n_i} =1.5\times 10^{10}
{V_T} = \frac{kT}{q} q \times {V_T} = kT(q is charge of electron) kT = 25meV E_{F_P} (Fermi Level of P-Type doped Si) E_{F_i}(Fermi Level of intrinsic Si) E_{F_i} - E_{F_P} = kT\ln (\frac{N_A}{n_i}) E_{F_i} - E_{F_P} = 5\times10^{3}\ln(\frac{4\times10^{17}}{1.5\times10^{10}}) E_{F_i} - E_{F_P} = 0.457eV \therefore E_{F_P} moves down by 0.457eV


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